17x^2=3x

Solution for 17x^2=3x equation:

17x^2=3x

We move all terms to the left:

17x^2-(3x)=0

a = 17; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·17·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*17}=\frac{0}{34}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*17}=\frac{6}{34}
=3/17
$